y^2+2x-8y+10=0

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Solution for y^2+2x-8y+10=0 equation:


Simplifying
y2 + 2x + -8y + 10 = 0

Reorder the terms:
10 + 2x + -8y + y2 = 0

Solving
10 + 2x + -8y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + 2x + -8y + -10 + y2 = 0 + -10

Reorder the terms:
10 + -10 + 2x + -8y + y2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 2x + -8y + y2 = 0 + -10
2x + -8y + y2 = 0 + -10

Combine like terms: 0 + -10 = -10
2x + -8y + y2 = -10

Add '8y' to each side of the equation.
2x + -8y + 8y + y2 = -10 + 8y

Combine like terms: -8y + 8y = 0
2x + 0 + y2 = -10 + 8y
2x + y2 = -10 + 8y

Add '-1y2' to each side of the equation.
2x + y2 + -1y2 = -10 + 8y + -1y2

Combine like terms: y2 + -1y2 = 0
2x + 0 = -10 + 8y + -1y2
2x = -10 + 8y + -1y2

Divide each side by '2'.
x = -5 + 4y + -0.5y2

Simplifying
x = -5 + 4y + -0.5y2

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